SUMMARY Phys 2523 (University Physics II) Compiled by Prof. Erickson. F e (r )=q E(r ) dq r 2 ˆr = k e E = V. V (r )=k e r = k q i. r i r.

Similar documents
Where k = 1. The electric field produced by a point charge is given by

Part 4: Electromagnetism. 4.1: Induction. A. Faraday's Law. The magnetic flux through a loop of wire is

Physics 208, Spring 2016 Exam #3

n Higher Physics 1B (Special) (PHYS1241) (6UOC) n Advanced Science n Double Degree (Science/Engineering) n Credit or higher in Physics 1A

Louisiana State University Physics 2102, Exam 3 April 2nd, 2009.

b) (4) How large is the current through the 2.00 Ω resistor, and in which direction?

Gen. Phys. II Exam 2 - Chs. 21,22,23 - Circuits, Magnetism, EM Induction Mar. 5, 2018

Physics / Higher Physics 1A. Electricity and Magnetism Revision

Describe the forces and torques exerted on an electric dipole in a field.

Physics GRE: Electromagnetism. G. J. Loges 1. University of Rochester Dept. of Physics & Astronomy. xkcd.com/567/

PHY102 Electricity Course Summary

Chapter 1: Electrostatics

Alternating Current Circuits

Chapter 31. Faraday s Law

Quiz 4 (Discussion Session) Phys 1302W.400 Spring 2018

we can said that matter can be regarded as composed of three kinds of elementary particles; proton, neutron (no charge), and electron.

Final on December Physics 106 R. Schad. 3e 4e 5c 6d 7c 8d 9b 10e 11d 12e 13d 14d 15b 16d 17b 18b 19c 20a

Principles of Physics II

Electromagnetic Induction Faraday s Law Lenz s Law Self-Inductance RL Circuits Energy in a Magnetic Field Mutual Inductance

Physics Will Farmer. May 5, Physics 1120 Contents 2

Yell if you have any questions

SUGGESTED LESSON PLANS FOR PHY 097 SEMESTER NOV10 Text Book : PHYSICS FOR SCIENTISTS & ENGINEERS WITH MODERN PHYSICS BY GIANCOLI, FOURTH EDITION

Physics 2B Spring 2010: Final Version A 1 COMMENTS AND REMINDERS:

Fundamental Constants

Exam 3 Topics. Displacement Current Poynting Vector. Faraday s Law Self Inductance. Circuits. Energy Stored in Inductor/Magnetic Field

Chapter 31. Faraday s Law

Louisiana State University Physics 2102, Exam 2, March 5th, 2009.

Name (Last, First): You may use only scientific or graphing calculators. In particular you may not use the calculator app on your phone or tablet!

Electrical polarization. Figure 19-5 [1]

Exam 2 Solutions. Note that there are several variations of some problems, indicated by choices in parentheses.

University of Colorado at Boulder Summer 2017, Session B Tuesday, July 11 - Friday, August 11. Prof. Mik Sawicki PHYS 1120 COURSE CALENDAR WEEK 1

Handout 10: Inductance. Self-Inductance and inductors

r where the electric constant

2426 Required Topics (May 4, 2012 draft) Halliday, FUNDAMENTALS OF PHYSICS, 9e Required topics are in bold text. Optional topics are in normal text.

Mansfield Independent School District AP Physics C: Electricity and Magnetism Year at a Glance

Ch. 23 Electromagnetic Induction, AC Circuits, And Electrical Technologies

Yell if you have any questions

AP Physics C. Magnetism - Term 4

Exam 4 Solutions. a. 1,2,and 3 b. 1 and 2, not 3 c. 1 and 3, not 2 d. 2 and 3, not 1 e. only 2

Physics (2) Dr. Yazid Delenda

Physics 2102 Gabriela González. Marathon review of the course: 15 weeks in ~60 minutes!

5) Ohm s Law gives the relationship between potential difference and current for a.

Physics 1B Spring 2010: Final Version A 1 COMMENTS AND REMINDERS:

Oscillations and Electromagnetic Waves. March 30, 2014 Chapter 31 1

Last time. Ampere's Law Faraday s law

Electromagnetic Induction (Chapters 31-32)

Waves. Decibels. Chapter 21: Dimension

Physics 112. Study Notes for Exam II

AP Physics C. Electricity - Term 3

University Of Pennsylvania Department of Physics PHYS 141/151 Engineering Physics II (Course Outline)

Solutions to these tests are available online in some places (but not all explanations are good)...

ELECTRO MAGNETIC INDUCTION

1) Opposite charges and like charges. a) attract, repel b) repel, attract c) attract, attract

Yell if you have any questions

PHYS General Physics for Engineering II FIRST MIDTERM

ELECTROMAGNETIC INDUCTION

fiziks Institute for NET/JRF, GATE, IIT-JAM, JEST, TIFR and GRE in PHYSICAL SCIENCES

Sliding Conducting Bar

EXAM 3: SOLUTIONS. B = B. A 2 = BA 2 cos 0 o = BA 2. =Φ(2) B A 2 = A 1 cos 60 o = A 1 2 =0.5m2

Physics 2020 Exam 2 Constants and Formulae

MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Physics Spring 2014 Final Exam Equation Sheet. B( r) = µ o 4π

Get Discount Coupons for your Coaching institute and FREE Study Material at ELECTROMAGNETIC INDUCTION

8. (6) Consider the circuit here with resistors R A, R B and R C. Rank the

Chapter 33. Alternating Current Circuits

Outline of College Physics OpenStax Book

On my honor, I have neither given nor received unauthorized aid on this examination.

Physics 208, Spring 2016 Exam #2

General Physics (PHY 2140)

Exam 2 Solutions. Prof. Darin Acosta Prof. Greg Stewart March 27, b 5Ω ->i 1 <- i 2 5Ω. 3V 10Ω 6 V - - i 3 d c 10Ω

ELECTROMAGNETIC OSCILLATIONS AND ALTERNATING CURRENT

r r 1 r r 1 2 = q 1 p = qd and it points from the negative charge to the positive charge.

Student number: Question # Mark Maximum Mark. Multiple Choice 20

PHY2049 Fall11. Final Exam Solutions (1) 700 N (2) 350 N (3) 810 N (4) 405 N (5) 0 N

Physics Physics 2102

21 MAGNETIC FORCES AND MAGNETIC FIELDS

Induction and Inductance

Exam 2, Phy 2049, Spring Solutions:

Physics Jonathan Dowling. Final Exam Review

Active Figure 32.3 (SLIDESHOW MODE ONLY)

Maxwell s equations and EM waves. From previous Lecture Time dependent fields and Faraday s Law

Self-inductance A time-varying current in a circuit produces an induced emf opposing the emf that initially set up the time-varying current.

A) n 1 > n 2 > n 3 B) n 1 > n 3 > n 2 C) n 2 > n 1 > n 3 D) n 2 > n 3 > n 1 E) n 3 > n 1 > n 2

ALI RAZA KAMAL EXERCISE NOTES

On my honor, I have neither given nor received unauthorized aid on this examination.

RLC Circuit (3) We can then write the differential equation for charge on the capacitor. The solution of this differential equation is

Chapters 34,36: Electromagnetic Induction. PHY2061: Chapter

PHYS 202 Notes, Week 6

1 Phasors and Alternating Currents

College Physics 10th edition

Chapter 32. Inductance

Questions A hair dryer is rated as 1200 W, 120 V. Its effective internal resistance is (A) 0.1 Ω (B) 10 Ω (C) 12Ω (D) 120 Ω (E) 1440 Ω

University of the Philippines College of Science PHYSICS 72. Summer Second Long Problem Set

PHYS 1441 Section 001 Lecture #23 Monday, Dec. 4, 2017

Exam 2 Solutions. Applying the junction rule: i 1 Applying the loop rule to the left loop (LL), right loop (RL), and the full loop (FL) gives:

AP Physics C. Electricity and Magne4sm Review

Version 001 CIRCUITS holland (1290) 1

EM Oscillations. David J. Starling Penn State Hazleton PHYS 212

Magnets. Domain = small magnetized region of a magnetic material. all the atoms are grouped together and aligned

Self-Inductance. Φ i. Self-induction. = (if flux Φ 1 through 1 loop. Tm Vs A A. Lecture 11-1

Inductance, Inductors, RL Circuits & RC Circuits, LC, and RLC Circuits

Transcription:

SUMMARY Phys 53 (University Physics II) Compiled by Prof. Erickson q 1 q Coulomb s Law: F 1 = k e r ˆr where k e = 1 4π =8.9875 10 9 N m /C, and =8.85 10 1 C /(N m )isthepermittivity of free space. Generally, F e (r )=q E(r ) Electric Field (N/C=V/m): q i E(r )=k e r ˆr = k r i r e qi r i r 3 (distribution of point charges) i i dq E(r )=k e r ˆr = k e q i r r dq r r 3 (continuous distribution) where dq = ρd 3 r, and ρ is the charge density. In steady-state, the electrical force is conservative, and the electric field can be derived from a potential V: E = V where is the gradient operator, = ˆx d dx + ŷ d dy + ẑ d dz in rectangular coordinates. Potential Energy (J): B U = q E ds A Electric Potential (V=J/C): V = U/q ; V = U/q q i V (r )=k e r = k q i e r i r i i dq V (r )=k e r = k e dq r r (distribution of point charges) (continuous distribution) Electric charge is quantized in units of e =1.60 10 19 C. An electron volt, ev =1.60 10 19 J. Electric Flux (N m /C=V m): Φ E = E da surface

Gauss s Law: Φ E = E da = Q inside surface (integral form) E = ρ (differential form) A conductor in electrostatic equilibrium has the following properties: 1. The electric field is zero everywhere inside the conductor.. Any net charge on the conductor resides entirely on its surface. 3. The electric field just outside the conductor is perpendicular to its surface and has a magnitude σ/,whereσ is the surface charge density at that point. 4. On an irregularly shaped conductor, the surface charge density is greatest where the radius of curvature of the surface is the smallest. 5. The potential is constant everywhere inside a conductor and equal to its value at the surface. Capacitance (F): C Q V and the energy stored in a capacitor is U = 1 C( V ). A dielectric material is composed of electric dipoles of magnitude p = aq, wherea is the dipole separation. A background electric field exerts a torque τ = p E on the dipoles. The potential energy of the system of an electric dipole in an electric field is U = p E. The potential energy of the dipoles reduces the potential difference in a capacitor, V = V κ, and C = κc where κ is the dielectric constant. The alignment of its dipoles results in an induced electric field (E ind ) that reduces the background electric field (E ) inside the dielectric to a value E = E E ind. A charge density σ ind = κ 1 κ σ is induced on its surface. Its dielectric strength is the maximum electric field that can be applied to the dielectric before its insulating properties break down and it begins to conduct. The capacitance of a parallel-plate capacitor is C = κ A d where A is the area of each plate, and d is the plate separation. Energy Density (J/m 3 ): u = E is the energy density contained in an electric field, where = κ.

Electrical Current (A=C/s): I = dq dt Ohm s Law: J = σe where J = nqv d is the current density, and σ is the conductivity. The resistivity ρ =1/σ = m e /(nq τ) in units of Ω m, where τ is the mean time between collisions. Over a limited temperature range, the resistivity of a conductor varies approximately linearly with temperature, ρ = ρ [1 + α(t T )], where α = 1 ρ ρ T is the temperature coefficient of resistivity. Resistance, R can be expressed similarly. Resistance (Ω=V/A): R V I Note that this equation, V = IR, is also referred to as Ohm s law. In terms of the resistivity, R = ρl/a, wherel is the length and A is the cross-sectional area of the material. Electrical Power (W): P = I V = I R = ( V ) R The emf of a battery is the maximum possible voltage that the battery can provide between its terminals. The terminal voltage will be V = Ir,wherer is the internal resistance of the battery. Combinations of Circuit Elements: 1 = 1 C eq i C i R eq = R i i (series combination) (series combination) C eq = C i i 1 = 1 R eq i R i (parallel combination) (parallel combination) Kirchhoff s Rules: Iin = I out (junction rule) V =0 closed loop (loop rule) 3

RC Circuits: Charging: q = q 1 e t/τ ; I = I e t/τ where q is the charge on the capacitor at time t, q = C( V ) is the equilibrium (fully charged) value of the charge, I = V/R is the current at t = 0, and τ = RC is the time constant of the dc circuit. Discharging: q = q e t/τ ; I = q RC e t/τ where q is the charge at t = 0. Magnetic Force on Particle: F B = qv B; F B = vb sin θ Gyroradius: r g = mv q B where the sense of rotation for a negatively charged particle follows the right-hand rule. When placed in a force field, F, in addition to a magnetic field, B, a charged particle s gyrocenter will drift with a velocity: v drift = F B qb ; v drift = F q B sin θ in order that the net force on the particle be zero. For example, when the additional force is the electrical force, a charged particle will drift such that F net = q(e + v B) = 0. Solving for the velocity of its gyrocenter: v drift = E B B ; v drift = E B sin θ Force on a Current Segment: F = IL B; F = ILB sin θ Torque on a Current Loop: where the magnetic moment is µ = NIA. τ = NIA B = µ B; τ = NIAB sin θ 4

Magnetic Field Due to Currents (T): Long, straight wire: Center of a current loop: Center of a partial current loop: Interior of a solenoid: B = µ I πr B = Nµ I R B = Nµ Iθ 4πR B = µ ni = µ NI where µ =4π 10 7 T m/a, N is the number of turns, and the direction of B is found using the right-hand rule. Ampere s Law: B d = µ I enclosed Biot-SavartLaw: db = µ I 4π d ˆr r Energy Density (J/m ): u = B µ Magnetic Flux (Wb=T m ): Φ B = B A = BAcos θ Faraday s Law (V): Motional Emf: = N dφ B dt = vbl Electrical generator: = NBAω sin ωt = max sin ωt where ω =πf is the angular frequency, and max = NBAω Lenz s law is stated as follows: The induced emf resulting from a changing magnetic flux has a polarity that leads to an induced current whose direction is such that the induced magnetic field opposes the original flux change. This statement is a consequence of the law of conservation of energy. 5

Inductance (H): Self Inductance: L = NΦ B I = L I t Energy stored in inductor: U = 1 LI Mutual Inductance: M = N SΦ S I P = M I P t Transformers: V S V P = N S N P I S I P = N P N S where the subscript P refers to the primary coil and subscript S refers to the secondary coil. AC Circuits: The output of an AC generator is sinusoidal, the voltage varies as V = V max sin ωt where ω = πf is the angular frequency, and f is the linear frequency. voltage are The rms current and I rms = I max ; V rms = V max The voltage and current across a resistor are in phase V R,rms = I rms R The voltage across a capacitor lags the current by 90, and where the X C = 1 ωc V C,rms = I rms X C is the capacitive reactance. The voltage across an inductor leads the current by 90, and V L,rms = I rms X L where the X C = ωl is the inductive reactance. 6

RLC Series Circuit: Ohm s law for the LRC series circuit reads V max = I max Z where Z = R +(X L X C ) is the impedence of the circuit. The phase angle φ between the current and the voltage obeys tan φ = X L X C R The power delivered by the generator is dissipated in the resistor; there is no power loss in the ideal capacitor or inductor. P ave = I rmsr = I rms V rms cos φ where the voltage across the resistor is V R = V rms cos φ. Resonance in a Series RLC Circuit: According to Ohm s law, the rms current is maximum when the impedence is a minimum. The minimum value of the impedence is R and occurs when X L = X C. This occurs at the resonant frequency: f = 1 π LC Maxwell s Equations: E = ρ B =0 E = db dt B = µ j + µ de dt Electromagnetic Waves/Light: c = 1 µ =.9979... 10 8 m/s v = fλ = 1 µ 7

Average energy density: ū = 1 E max + 1 µ B max = E rms = 1 µ B rms where E = vb, E rms = E max / and B rms = B max / Intensity (Poynting vector) (W/m ): S = 1 µ E B; S = vu, S = vū Doppler effect: f obs = f source 1 ± v rel c Reflection: θ i = θ r Index of refraction: n = c v 1; λ n = λ n Snell s Law of Refraction: n 1 sin θ 1 = n sin θ Total Internal Reflection: sin θ c = n n 1, where (n 1 >n ) Single-slit diffraction: sin θ dark = mλ,m= ±1, ±,... W Double-slit diffraction: sin θ bright = mλ,m=0, ±1, ±,... d sin θ dark = m + 1 λ,m=0, ±1, ±,... d Diffraction grating: sin θ bright = mλ,m=0, ±1, ±,... d Additional properties: Interference, Fermat s Principle, Dispersion, Huygens Principle 8

Quantum Effects: (h = Planck s constant = 6.66... 10 34 J s) Photon: E = hf, p = h λ = hf c Photoelectric effect: hf = KE max + W, where W = work function debroglie wavelength: λ = h p Heisenberg Uncertainty Principle: p x x h 4π, E t h 4π Bohr model (1 valence electron): r n = r 1n Z eff, where r 1 =5.9 10 11 m = Bohr radius E n = (13.6 ev) Z eff n Quantum numbers: Principal Quantum Number: n = 1,, 3,... (E n = (13.6 ev) Z eff n ) Orbital Quantum Number: l = 0, 1,,..., (n 1) (L = l(l + 1) h π ) Magnetic Quantum Number: m l = l,..., 1, 0, 1,,..., l (L z = m l h π ) Spin Quantum Number: m s = ± 1 The Pauli Exclusion Principle states that no two electrons in an atom may have the same set of quantum numbers. 9